# Bath in Winters Solution Codechef

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## Bath in Winters Solution Codechef

A geyser has a capacity of X litres of water and a bucket has a capacity of Y litres of water.

One person requires exactly 2 buckets of water to take a bath. Find the maximum number of people that can take bath using water from one completely filled geyser.

### Input Format

• First line will contain T, number of test cases. Then the test cases follow.
• Each test case contains a single line of input, two integers X,Y.

### Output Format

For each test case, output the maximum number of people that can take bath.

• 1≤T≤1000
• 1≤X,Y≤100

```4
10 6
25 1
100 10
30 40```

```0
12
5
0```

### Explanation

Test Case 1: One bucket has a capacity of 6 litres. This means that one person requires 2⋅6=12 litres of water to take a bath. Since this is less than the total water present in geyser, 0 people can take bath.

Test Case 2: One bucket has a capacity of 1 litre. This means that one person requires 2⋅1=2 litres of water to take a bath. The total amount of water present in geyser is 25 litres. Thus, 12 people can take bath. Note that 1 litre water would remain unused in the geyser.

Test Case 3: One bucket has a capacity of 10 litres. This means that one person requires 20⋅10=20 litres of water to take a bath. The total amount of water present in geyser is 100 litres. Thus, 5 people can take bath. Note that 0 litres of water would remain unused in the geyser after this.

## SOLUTION

Program: Bath in Winters Solution Codechef in Python

```for _ in range(int(input())):
w,b=map(int,input().split(" "))
r=w//(2*b)
print(r)```

Program: Bath in Winters Solution Codechef in C++

```#include<bits/stdc++.h>
using namespace std;

int main(){

int a,b,t;
cin>>t;
while(t--){
cin>>a>>b;
int n=a/(b*2);
cout<<n<<"\n";
}

return 0;
}```

Program: Bath in Winters Solution Codechef in Java

```import java.util.Scanner;
import java.lang.*;
import java.io.*;

class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
for(int i=0;i<n;i++){
int z=sc.nextInt();
int x=sc.nextInt();
System.out.println(z/(x*2));
}
}
}```