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**Count Maximum Teams Amazon OA Solution**

Amazon is hosting a team hackathon.

- Each team will have exactly teamSize developers.
- A developer’s skill level is denoted by skill[i].
- The difference between the maximum and minimum skill levels within a team cannot exceed a threshold, maxDiff.

Determine the maximum number of teams that can be formed from the contestants.

E**xample**

skill = [3, 4, 3, 1, 6, 5]

team5ize = 3

maxDiff = 2

At most, 2 teams can be formed: [3, 3, 1] and [4, 6, 5].

The difference between the maximum and minimum skill levels is 2 in each case,

which does not exceed the threshold value oft.

**Function Description**

Complete the function countMaximumTeams in the editor below.

countMaximumTeams has the following parameter(s):

- int skill[n]: the developers’ skill levels
- int teamSize: the number of developers to make up a team
- int maxDiff: the threshold value

**Returns:**

- int: the maximum number of teams that can be formed at one time

**SOLUTION**

**Program:** **Count Maximum Teams Amazon OA Solution** in C++

#include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; vector<int> a(n); int team, diff; cin>>team>>diff; sort(a.begin(),a.end()); int i=0, j=team-1, cnt=0; while(j<n){ if(a[j]-a[i]<=diff){ cnt++; i=j+1; j=j+team; } else{ i++; j++; } } cout<<cnt; return 0; }

**Program:****Count Maximum Teams Amazon OA Solution** in Java

static int countMaximumTeams(List<int> skill, int teamSize, int maxDiff) { skill.Sort(); int i = 0; int j = teamSize - 1; int count = 0; while (j < skill.Count) { if (skill[j] - skill[i] <= maxDiff) { count++; i = j + 1; j = i + 2; } else { i++; j++; } } return count; }

**Program:** **Count Maximum Teams Amazon OA Solution** in Python

def countMaximumTeams(skill, teamSize, maxDiff): teams = 0 n = len(skill) if n < teamSize: return teams skill.sort() for i in range(n): if i + teamSize - 1 < n: diff = skill[i + teamSize - 1] - skill[i] if diff <= maxDiff: teams += 1 return teams

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