TCS Examination EXAMTIME Solution Codechef

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Codechef TCS Examination EXAMTIME Solution

Two friends, Dragon and Sloth, are writing a computer science examination series. There are three subjects in this series: DSADSA, TOCTOC, and DMDM. Each subject carries 100100 marks.

You know the individual scores of both Dragon and Sloth in all 33 subjects. You have to determine who got a better rank.

The rank is decided as follows:

The person with a bigger total score gets a better rank
If the total scores are tied, the person who scored higher in DSADSA gets a better rank
If the total score and the DSADSA score are tied, the person who scored higher in TOCTOC gets a better rank
If everything is tied, they get the same rank.

Input Format

The first line of input contains a single integer TT, denoting the number of test cases. The description of TT test cases follows.
The first line of each test case contains three space-separated integers denoting the scores of Dragon in DSADSA, TOCTOC and DMDM respectively.
The second line of each test case contains three space-separated integers denoting the scores of Sloth in DSADSA, TOCTOC and DMDM respectively.

Output Format

For each test case, if Dragon got a better rank then output "Dragon", else if Sloth got a better rank then output "Sloth". If there was a tie then output "Tie". Note that the string you output should not contain quotes.
The output is case insensitive. For example, If the output is “Tie” then “TiE”, “tiE”, “tie”, etc are also considered correct.

Constraints

1≤T≤10001≤T≤1000
Each score of both Dragon and Sloth lies between 00 and 100100.

Subtasks

Subtask #1 (100 points): Original constraints

Sample Input 1

Sample Output 1

SLOTH
TIE
DRAGON
DRAGON

Explanation

For the first test case, Sloth and Dragon have the same total score but Sloth gets a better rank because he has a higher score in DSADSA.
For the second test case, Sloth and Dragon have the same rank because they have the same score among all subjects.
For the third test case, Dragon gets a better rank because he has a greater total score.
For the fourth test case, Sloth and Dragon have the same total score and same DSADSA score. Dragon gets a better rank because he has a greater TOCTOC score.

Click Below for solution

Solution

Program: TCS Examination EXAMTIME Solution in C++

#include <iostream>
using namespace std;

int main() {
	int t;
	cin >>t;
	for(int i=0;i<t;i++)
	{
	    int x,y,z;
	    int a,b,c;
	    cin >>x>>y>>z;
	    cin >>a>>b>>c;
	    if((x+y+z)>(a+b+c))
	    {
	        cout <<"Dragon"<<"\n";
	    }
	    else if((a+b+c)>(x+y+z))
	    {
	        cout<<"Sloth"<<"\n";
	    }
	    else if((x+y+z)==(a+b+c))
	    {
	        if(x>a)
	        {
	            cout<<"Dragon"<<"\n";
	        }
	        else if(x<a)
	        {
	            cout<<"Sloth"<<"\n";
	        }
	        else
	        {
	            if(y>b){cout<<"Dragon"<<"\n";}
	            else if(y<b){cout<<"Sloth"<<"\n";}
	            else{cout<<"Tie"<<"\n";}
	        }
	    }
	}
	return 0;
}

Program: TCS Examination EXAMTIME Solution in Java

import java.util.*;
import java.lang.*;
import java.io.*;

class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner sc = new Scanner(System.in);
		int t = sc.nextInt();
		while(t-- > 0){
		    int dd = sc.nextInt();
		     int dt = sc.nextInt();
		      int ddm = sc.nextInt();
		       int sd = sc.nextInt();
		        int st = sc.nextInt();
		         int sdm = sc.nextInt();
		        int dragon = dd+dt+ddm;
		        int sloth = sd+st+sdm;
		        if(dragon > sloth){
		            System.out.println("DRAGON");
		        }
		        else if(sloth > dragon){
		            System.out.println("SLOTH");
		        }
		        else if(dragon == sloth && dd>sd){
		            System.out.println("DRAGON");
		        }
		        else if(dragon == sloth && sd>dd){
		            System.out.println("SLOTH");
		        }
		        else if(dragon == sloth && dd == sd && dt>st){
		            System.out.println("DRAGON");
		        }
		        else if(dragon == sloth && dd == sd && st>dt){
		            System.out.println("SLOTH");
		        }
		        else {
		            System.out.println("TIE");
		        }
		}
	}
}

Program: TCS Examination EXAMTIME Solution in Python

for _ in range(int(input())):
    d = list(map(int,input().split()))
    s = list(map(int,input().split()))
    if sum(d)<sum(s):
        print("sloth")
    elif sum(d)>sum(s):
        print("dragon")
    else:
        f = 0
        for i in range(3):
            if d[i]<s[i]:
                print("sloth")
                break
            elif d[i]>s[i]:
                print("dragon")
                break
            else:
                f+=1
        if f==3:
            print("tie")