Which Fuel is Cheaper CHEAPFUEL Solution Codechef

Which Fuel is Cheaper CHEAPFUEL Solution

The current price of petrol is X rupees, and the current price of diesel is Y rupees. At the start of each month, the price of petrol increases by A rupees and the price of diesel increases by B rupees. Chef is curious to know which fuel costs less at the end of the Kth month. If petrol is cheaper than diesel at the end of Kth month, then print PETROL. If diesel is cheaper than petrol at the end of the Kth month, then print DIESEL. If both the fuels have the same price at the end of the Kth month, then print SAME PRICE.

Input Format

  • The first line of input contains a single integer T, denoting the number of test cases. The description of T test cases follows.
  • Each test case consists of a single line of input, containing five space-separated integers X,Y,A,B,K.

Output Format

For each test case,

  • Print PETROL if petrol is cheaper than diesel.
  • Print DIESEL if diesel is cheaper than petrol.
  • Print SAME PRICE otherwise.

Note: The output is case-insensitive. You can print each character in either lower-case or upper-case.

Constraints

  • 1≤T≤1000
  • 1≤K≤1000
  • 0≤X,Y,A,B≤1000

Subtasks

  • Subtask 1 (100 points): Original constraints

Sample Input 1

3
1 1 1 1 1
2 1 2 1 2
2 2 1 1 2

Sample Output 1

SAME PRICE
DIESEL
SAME PRICE

Explanation

  • Test case 1: Initially, the price of petrol is 1 rupee and the price of diesel is 1 rupee. Since A=1 and B=1, the prices of both petrol and diesel increase by 1 rupee at the start of every month. So, at the start of the first month, the price of petrol becomes 1+1=2 rupees and the price of diesel becomes 1+1=2 rupees. By the end of the first month, the price of petrol and diesel are both 2 rupees and hence they both have the same price.
  • Test case 2: Initially, the price of petrol is 2 rupees and the price of diesel is 1 rupee. Since A=2 and B=1, the price of petrol increases by 2 rupee and the price of diesel increases by 1 rupee at the start of every month. It follows that at the start of the first month, the price of petrol becomes 2+2=4 rupees and the price of diesel becomes 1+1=2 rupees. And by the start of the second month, the price of petrol becomes 4+2=6 rupees and the price of diesel becomes 2+1=3 rupees. By the end of the second month, the prices of petrol and diesel are 6 rupees and 3 rupees respectively and hence diesel is cheaper than petrol.
  • Test case 3: Initially, the price of petrol is 2 rupee and the price of diesel is 2 rupee. Since A=1 and B=1, the price of petrol increases by 1 rupee and the price of diesel increases by 1 rupee at the start of every month. It follows that at the start of the first month, the price of petrol becomes 2+1=3 rupees and the price of diesel becomes 2+1=3 rupees. And by the start of the second month, the price of petrol becomes 3+1=4 rupees and the price of diesel becomes 3+1=4 rupees. By the end of the second month, the prices of petrol and diesel are both 4 rupees and hence both have the same prices.

SOLUTION

Program Python: Which Fuel is Cheaper CHEAPFUEL Solution in Python

# cook your dish here
for _ in range(int(input())):
    a,b,c,d,e = map(int, input().split())
    p= a + (c * e)
    d = b + (d * e)
    
    if (p < d):
        print("PETROL")
    elif (d < p):
        print("DIESEL")
    else:
        print("SAME PRICE")

Program C++: Which Fuel is Cheaper CHEAPFUEL Solution in C++

#include <iostream>
using namespace std;
int main() {
    int t;
    cin >> t;
    while(t--){
    
    int a,b,c,d,e,p,dp;
    cin >> a >> b >> c >> d >> e;
    p = a + (c * e);
    dp = b + (d * e);
    
    if (p < dp){
        cout << "PETROL" << endl;
    }
    else if (dp < p){
        cout << "DIESEL" << endl;
    }
    else{
        cout << "SAME PRICE" << endl;
    }
    }
    return 0;
}

Program Java: Which Fuel is Cheaper CHEAPFUEL Solution in Java

import java.util.Scanner;
import java.lang.*;
import java.io.*;
class Codechef
{
    public static void main (String[] args) throws java.lang.Exception
    {
        Scanner input = new Scanner(System.in);
        int t = input.nextInt();
        while (t > 0){
            
            int a = input.nextInt();
            int b = input.nextInt();
            int c = input.nextInt();
            int d = input.nextInt();
            int e = input.nextInt();
            
            int p = a + (c * e);
            int dp = b + (d * e);
            
            if (p < dp){
                System.out.println("PETROL");
            }
            else if (dp < p){
                System.out.println("DIESEL");
            }
            else{
                System.out.println("SAME PRICE");
            }
            t = t - 1;
        }
    }
}

November Long Challenge 2021 Solution

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