Three Boxes Codechef October Long Challenge

Three Boxes Solution

Chef has 3 boxes of sizes A, B, and C respectively. He puts the boxes in bags of size D (A≤B≤C≤D). Find the minimum number of bags Chef needs so that he can put each box in a bag. A bag can contain more than one box if the sum of sizes of boxes in the bag does not exceed the size of the bag.

Input Format

  • The first line contains T denoting the number of test cases. Then the test cases follow.
  • Each test case contains four integers A, B, C, and D on a single line denoting the sizes of the boxes and bags.

Output Format

For each test case, output on a single line the minimum number of bags Chef needs.

Constraints

  • 1≤T≤100
  • 1≤A≤B≤C≤D≤100

Subtasks

Subtask 1 (100 points): Original constraints

Sample Input 1

3
2 3 5 10
1 2 3 5
3 3 4 4

Sample Output 1

1
2
3

Explanation

  • Test case 1: The sum of sizes of boxes is 2+3+5=10 which is equal to the size of a bag. Hence Chef can put all three boxes in a single bag.
  • Test case 2: Chef can put boxes of size 1 and 3 in one bag and box of size 2 in another bag.
  • Test case 3: Chef puts all the boxes in separate bags as there is no way to put more than one box in a single bag.

SOLUTION

Program Python: Three Boxes Solution in Python

for _ in range (int(input())):
    a,b,c,d=map(int,input().split())
    if a+b+c<=d:
        print(1)
    elif a+c<=d:
        print(2)
    elif b+a<=d:
        print(2)
    else:
        print(3)

October Long Challenge 2021

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