Table of Contents
Three Boxes Solution
Chef has 3 boxes of sizes A, B, and C respectively. He puts the boxes in bags of size D (A≤B≤C≤D). Find the minimum number of bags Chef needs so that he can put each box in a bag. A bag can contain more than one box if the sum of sizes of boxes in the bag does not exceed the size of the bag.
- The first line contains T denoting the number of test cases. Then the test cases follow.
- Each test case contains four integers A, B, C, and D on a single line denoting the sizes of the boxes and bags.
For each test case, output on a single line the minimum number of bags Chef needs.
Subtask 1 (100 points): Original constraints
Sample Input 1
3 2 3 5 10 1 2 3 5 3 3 4 4
Sample Output 1
1 2 3
- Test case 1: The sum of sizes of boxes is 2+3+5=10 which is equal to the size of a bag. Hence Chef can put all three boxes in a single bag.
- Test case 2: Chef can put boxes of size 1 and 3 in one bag and box of size 2 in another bag.
- Test case 3: Chef puts all the boxes in separate bags as there is no way to put more than one box in a single bag.
Program Python: Three Boxes Solution in Python
for _ in range (int(input())): a,b,c,d=map(int,input().split()) if a+b+c<=d: print(1) elif a+c<=d: print(2) elif b+a<=d: print(2) else: print(3)