Chess Match Codechef Solution

Chess Match Solution Problem Code: BLITZ3_2

In a Chess match “a + b”, each player has a clock which shows aa minutes at the start and whenever a player makes a move, bb seconds are added to this player’s clock. Time on a player’s clock decreases during that player’s turns and remains unchanged during the other player’s turns. If the time on some player’s clock hits zero (but not only in this case), this player loses the game.

There’s a 3 + 2 blitz chess match. After NN turns (i.e. ⌊N+12⌋⌊N+12⌋ moves made by white and ⌊N2⌋⌊N2⌋ moves made by black), the game ends and the clocks of the two players stop; they show that the players (white and black) have AA and BB seconds left respectively. Note that after the NN-th turn, b=2b=2 seconds are still added to the clock of the player that made the last move and then the game ends.

Find the total duration of the game, i.e. the number of seconds that have elapsed from the start of the game until the end.

Input

  • The first line of the input contains a single integer TT denoting the number of test cases. The description of TT test cases follows.
  • The first and only line of each test case contains three space-separated integers NN, AA and BB.

Output

For each test case, print a single line containing one integer — the duration of the game.

Constraints

  • 1≤T≤1051≤T≤105
  • 10≤N≤10010≤N≤100
  • 0≤A≤180+2⋅⌊N+12⌋0≤A≤180+2⋅⌊N+12⌋
  • 0≤B≤180+2⋅⌊N2⌋0≤B≤180+2⋅⌊N2⌋
  • for NN odd, A≥2A≥2
  • for NN even, B≥2B≥2
  • there is at least one valid game consistent with the input

Example Input

3
10 0 2
11 2 1
12 192 192

Example Output

378
379
0

Explanation

Example case 1: The total time given to both clocks after 1010 turns is 2⋅(180+10)=3802⋅(180+10)=380 seconds. The total time left at the end is 0+2=20+2=2 seconds. The duration of the game is 380−2=378380−2=378 seconds.

Example case 3: The total time given to both clocks after 1212 turns is 2⋅(180+12)=3842⋅(180+12)=384 seconds. The total time left at the end is 192+192=384192+192=384 seconds. The duration of the game is 384−384=0384−384=0 seconds.

Weekly Contest 247

Biweekly Contest 55

June Long Challenge 2021 Solutions

March Long Challenge 2021 Solutions

April Long Challenge 2021 Solutions

Codechef Long Challenge Solutions

February Long Challenge 2021

January Long Challenge 2021

November Challenge 2020 SOLUTION CodeChef

October Lunchtime 2020 CodeChef SOLUTIONS

Related :

Related :

Leave a Comment

20 + seventeen =