## Table of Contents

**1-bit and 2-bit Characters Solution**

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

**Example 1:**

Input: bits = [1, 0, 0]

Output: True

Explanation: The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.

**Example 2:**

Input: bits = [1, 1, 1, 0]

Output: False

Explanation: The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.

Note: 1 <= len(bits) <= 1000.bits[i] is always 0 or 1.

**SOLUTION**

**Program:** **1-bit and 2-bit Characters Solution** in Java

```
auto speedup = []() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
return nullptr;
}();
class Solution {
public:
bool isOneBitCharacter(vector<int>& bits) {
int i = bits.size() - 2;
while (i >= 0 && bits[i] > 0) i--;
return (bits.size() - i) % 2 == 0;
}
};
```