Page Contents
Prime Game SOLUTION SSEC0006
Hey guys, I hope you all are doing great.
Now lets start with the problem :
Before I start we can see in the question itself how well it’s been already explained but still if you guys have your doubts, continue with me.
Now lets try to understand what this question wants from us, If we see here A & B are the two ranges basically right.
So, what makes it so interesting there is a twist which question says Range A is now (A/2*B/2), As per our given explanation in the question. HOLD ON!!! is that right? NO! What if the Range A is (A*B)? and how we will know that what range value will come in Range A, Well I know most of you are smart and clever and already know what is the answer Really Great.
So what will be the Range A Value?
Compare them both, but what we have to compare ?
Let’s see that,
if (A/2*B/2) is around 600 okay we are just assuming its value, and (A*B) is around 800 so which one is smaller that value will be given to Range A because it’s the starting range right and obviously it is going to be smaller then Range B. Even the constraints says that
So, now we know which value will go where if it’s smaller then to Range A if its bigger then Range B.
I hope this First step is clear.
Now lets see what we have to do in the question.
I’m going to take my own prime number range, to make it more simple and clear.
Range A =5
Range B=20
Our first motive will be to get the prime numbers from 5 to 20
Prime Number from 5 to 20
“5 7 11 13 17 19” this are the prime numbers of our given range now lets TWIST THEM UP.
Now, we are going to find the values for (A*B) and (A/2*B/2)
So,
A*B= 5*20 = 100
A/2 * B/2 = 5/2 * 20/2 = 2 * 10 = 20 (Now here 5/2 will give float but we have to take integer).
So, we find our new ranges now okay. Let’s call them as
Range A = 20
Range B=100
Question is why this way why not Range A =100. Because it will start from smaller value to larger value. If you remember the CONSTRAINTS!
So, we are with our new ranges and prime value.
Now lets do the pairing of the prime numbers “5 7 11 13 17 19”
5*7 = 35
5*11 = 55
5*13 = 65
5*17 = 85
5*19 = 95
7*11 = 77
7*13 = 91
7*17 = 119
7*19 = 133
11*13 = 143
11*17 = 187
11*19 = 209
13*17 = 221
13*19 = 247
17*19 = 323
WOW! looks scary to me atleast.
So now we got our pair values lets see what will be the output of new Range A = 20 and Range B = 100
Let’s do it now,
A=20 B=100
20<= 5*7 <= 100
20 <= 35 <= 100 { TRUE}
Now I solved it in this manner to make it clear how it’s looks like, Let’s solve it directly now.
20 <= 35 <= 100 { TRUE}
20 <= 55 <= 100 { TRUE}
20 <= 65 <= 100 { TRUE}
20 <= 77 <= 100 { TRUE}
20 <= 85 <= 100 { TRUE}
20 <= 85 <= 100 { TRUE}
20 <= 91 <= 100 { TRUE}
20 <= 95 <= 100 { TRUE}
20 <= 119 <= 100 { FALSE}
20 <= 133 <= 100 { FALSE}
20 <= 143 <= 100 { FALSE}
20 <= 187 <= 100 { FALSE}
Now if you see I stopped after few False Because our limit is “Less Than or Equal to” 100.
You might also notice that why 77 is coming before 95 but while calculating the pairs it was after 95. It’s because we have to compare from smaller to larger, it will help while printing the Output.
So, Our Input was A=5 and B=20
Output: 5,7
5,11
5,13
7,11
5,17
5,19
7,13
I hope this will be enough to clear your doubt!
[REMEMBER ABOUT THE PAIRS CHECKING I CAN BE WRONG ALSO IN SAYING THAT 7,11 WILL COME BEFORE 5,17 DEPENDS ON ITS PAIR VALUE, OTHER THEN THE LOGIC IS CLEAR AND SIMPLE.]
KEEP CODING GUYS.
