**Chefina and Swap SOLUTION**

**Chefina and Swap SOLUTION**

You are given a positive number N. Consider the grouping S=(1,2,… ,N). You ought to pick two components of this succession and trade them.

A trade is decent if there is a number M (1≤M<N) with the end goal that the whole of the primary M components of the subsequent succession is equivalent to the aggregate of its last N−M components. Locate the quantity of pleasant trades.

Info

The main line of the info contains a solitary number T meaning the quantity of experiments. The portrayal of T experiments follows.

The solitary line of each experiment contains a solitary number N.

Yield

For each experiment, print a solitary line containing one number ― the quantity of decent trades.

Imperatives

1≤T≤106

1≤N≤109

Subtasks

Subtask #1 (10 focuses):

T≤10

N≤103

Subtask #2 (30 focuses):

T≤10

N≤106

Subtask #3 (60 focuses): unique imperatives

Model Input

5

1

2

3

4

7

Model Output

0

0

2

2

3

**LOGIC VIDEO HAS BEEN REMOVED**

Is it need any algorithm or it's implementation based question?

I think when there will be 3 days to end or 5 days then i think this codechef may permit till then i think we need to try our own put please share any logic we dont want code just logic will do thanks man

hey bro i think its not based on algorithm totally i think we need to find out the logic even in trying if u can do it please share the solutions here

hello can someone just tell me what would be the answer input 20 please, it would help me understand the problem statement.

i think 6

112

#include

using namespace std;

int main()

{

int t;

cin>>t;

while(t–)

{

int n,num;

cin >> n;

num = (n+1)/2;

if(num%2)

cout<<"0"<<endl;

else

cout<<(num/2)+1<<endl;

}

return 0;

}

Can someone point out the mistake?

For n=7

output must be 3

but your output will differ

this is not the correct logic

What is the output for n=12 and n=20? The example cases given in the question is not presenting the whole picture.

112

4 and 112

6

hw 112

119-4116

hw

can you please explain how the answer for 20 is 112 please

# cook your dish here

t=int(input())

import itertools

def chefswap(n,arr):

hell = list(itertools.combinations(range(n), 2))

m=0

for i,j in hell:

c=0

arr[i],arr[j]=arr[j],arr[i]

for k in range(n-1):

arr1=sum(arr[0:k+1:1])

arr2=sum(arr[k+1:n:1])

if arr1==arr2:

c=c+1

if c!=0:

m=m+1

arr[i],arr[j]=arr[j],arr[i]

return m

for _ in range(t):

n=int(input())

arr=[]

for i in range(1,n+1):

arr.append(i)

if n==1 or n==2:

print(0)

else:

result=chefswap(n,arr)

print(result)

There is time limit error.

what will be the output of n=8 and n=9? Please tell.

112

3 0

15 and 1 is a nice swap

16 and 2

17 and 3…..

How did you get 112 for n=20

Why 112 for n=20

How did you get 112 for n=20 please clarify my doubt

How did you get 112 for n=20?

what will the output for 11 and 12

please tell fast

4 and 4

It would be 112

It would be 112

What is the answer for 19?

Can you say me how did you get 112 for n=20?

what will be output for n=20?